0.12(6)+0.02x=0.04(12x)

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Solution for 0.12(6)+0.02x=0.04(12x) equation: 



0.12(6)+0.02x=0.04(12x)

We move all terms to the left:

0.12(6)+0.02x-(0.04(12x))=0

We add all the numbers together, and all the variables

0.02x-(+0.0412x)+0.126=0

We get rid of parentheses

0.02x-0.0412x+0.126=0

We add all the numbers together, and all the variables

-0.0212x+0.126=0

We move all terms containing x to the left, all other terms to the right

-0.0212x=-0.126

x=-0.126/-0.0212

x=5+0.02/0.0212

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