0.12(6)+0.2x=0.04(12+x)

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Solution for 0.12(6)+0.2x=0.04(12+x) equation: 



0.12(6)+0.2x=0.04(12+x)

We move all terms to the left:

0.12(6)+0.2x-(0.04(12+x))=0

We add all the numbers together, and all the variables

0.2x-(0.04(x+12))+0.126=0



We calculate terms in parentheses: -(0.04(x+12)), so:

0.04(x+12)

We multiply parentheses

0.04x+0.48

Back to the equation:

-(0.04x+0.48)



We get rid of parentheses

0.2x-0.04x-0.48+0.126=0

We add all the numbers together, and all the variables

0.16x-0.354=0

We move all terms containing x to the left, all other terms to the right

0.16x=0.354

x=0.354/0.16

x=2+0.034/0.16

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