0.12(y-3)+0.08y=0.16y-0.01(40)

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Solution for 0.12(y-3)+0.08y=0.16y-0.01(40) equation: 



0.12(y-3)+0.08y=0.16y-0.01(40)

We move all terms to the left:

0.12(y-3)+0.08y-(0.16y-0.01(40))=0

We add all the numbers together, and all the variables

0.12(y-3)+0.08y-(0.16y-0.014)=0

We add all the numbers together, and all the variables

0.08y+0.12(y-3)-(0.16y-0.014)=0

We multiply parentheses

0.08y+0.12y-(0.16y-0.014)-0.36=0

We get rid of parentheses

0.08y+0.12y-0.16y+0.014-0.36=0

We add all the numbers together, and all the variables

0.04y-0.346=0

We move all terms containing y to the left, all other terms to the right

0.04y=0.346

y=0.346/0.04

y=8+0.026/0.04

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