0.12(y-3)+0.10y=0.02y-0.1

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Solution for 0.12(y-3)+0.10y=0.02y-0.1 equation: 



0.12(y-3)+0.10y=0.02y-0.1

We move all terms to the left:

0.12(y-3)+0.10y-(0.02y-0.1)=0

We add all the numbers together, and all the variables

0.10y+0.12(y-3)-(0.02y-0.1)=0

We multiply parentheses

0.10y+0.12y-(0.02y-0.1)-0.36=0

We get rid of parentheses

0.10y+0.12y-0.02y+0.1-0.36=0

We add all the numbers together, and all the variables

0.2y-0.26=0

We move all terms containing y to the left, all other terms to the right

0.2y=0.26

y=0.26/0.2

y=1+0.06/0.2

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