0.12(y-4)+0.08y=0.04y-0.01(40)

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Solution for 0.12(y-4)+0.08y=0.04y-0.01(40) equation: 



0.12(y-4)+0.08y=0.04y-0.01(40)

We move all terms to the left:

0.12(y-4)+0.08y-(0.04y-0.01(40))=0

We add all the numbers together, and all the variables

0.12(y-4)+0.08y-(0.04y-0.014)=0

We add all the numbers together, and all the variables

0.08y+0.12(y-4)-(0.04y-0.014)=0

We multiply parentheses

0.08y+0.12y-(0.04y-0.014)-0.48=0

We get rid of parentheses

0.08y+0.12y-0.04y+0.014-0.48=0

We add all the numbers together, and all the variables

0.16y-0.466=0

We move all terms containing y to the left, all other terms to the right

0.16y=0.466

y=0.466/0.16

y=2+0.146/0.16

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