0.12(y-4)+0.10y=0.16y-0.01(30)

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Solution for 0.12(y-4)+0.10y=0.16y-0.01(30) equation: 



0.12(y-4)+0.10y=0.16y-0.01(30)

We move all terms to the left:

0.12(y-4)+0.10y-(0.16y-0.01(30))=0

We add all the numbers together, and all the variables

0.12(y-4)+0.10y-(0.16y-0.013)=0

We add all the numbers together, and all the variables

0.10y+0.12(y-4)-(0.16y-0.013)=0

We multiply parentheses

0.10y+0.12y-(0.16y-0.013)-0.48=0

We get rid of parentheses

0.10y+0.12y-0.16y+0.013-0.48=0

We add all the numbers together, and all the variables

0.06y-0.467=0

We move all terms containing y to the left, all other terms to the right

0.06y=0.467

y=0.467/0.06

y=7+0.047/0.06

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