0.12(y-4)+0.12y=0.20y-0.5

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Solution for 0.12(y-4)+0.12y=0.20y-0.5 equation:



0.12(y-4)+0.12y=0.20y-0.5
We move all terms to the left:
0.12(y-4)+0.12y-(0.20y-0.5)=0
We add all the numbers together, and all the variables
0.12y+0.12(y-4)-(0.20y-0.5)=0
We multiply parentheses
0.12y+0.12y-(0.20y-0.5)-0.48=0
We get rid of parentheses
0.12y+0.12y-0.20y+0.5-0.48=0
We add all the numbers together, and all the variables
0.04y+0.02=0
We move all terms containing y to the left, all other terms to the right
0.04y=-0.02
y=-0.02/0.04
y=-0.02/0.04

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