0.12(y-5)+0.04y=0.20y-1

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Solution for 0.12(y-5)+0.04y=0.20y-1 equation:



0.12(y-5)+0.04y=0.20y-1
We move all terms to the left:
0.12(y-5)+0.04y-(0.20y-1)=0
We add all the numbers together, and all the variables
0.04y+0.12(y-5)-(0.20y-1)=0
We multiply parentheses
0.04y+0.12y-(0.20y-1)-0.6=0
We get rid of parentheses
0.04y+0.12y-0.20y+1-0.6=0
We add all the numbers together, and all the variables
-0.04y+0.4=0
We move all terms containing y to the left, all other terms to the right
-0.04y=-0.4
y=-0.4/-0.04
y=+10

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