0.12(y-7)+0.20y=0.16y-0.2

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Solution for 0.12(y-7)+0.20y=0.16y-0.2 equation: 



0.12(y-7)+0.20y=0.16y-0.2

We move all terms to the left:

0.12(y-7)+0.20y-(0.16y-0.2)=0

We add all the numbers together, and all the variables

0.20y+0.12(y-7)-(0.16y-0.2)=0

We multiply parentheses

0.20y+0.12y-(0.16y-0.2)-0.84=0

We get rid of parentheses

0.20y+0.12y-0.16y+0.2-0.84=0

We add all the numbers together, and all the variables

0.16y-0.64=0

We move all terms containing y to the left, all other terms to the right

0.16y=0.64

y=0.64/0.16

y=4

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