0.12(y-8)+0.20y=0.04y-0.01(40)

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Solution for 0.12(y-8)+0.20y=0.04y-0.01(40) equation: 



0.12(y-8)+0.20y=0.04y-0.01(40)

We move all terms to the left:

0.12(y-8)+0.20y-(0.04y-0.01(40))=0

We add all the numbers together, and all the variables

0.12(y-8)+0.20y-(0.04y-0.014)=0

We add all the numbers together, and all the variables

0.20y+0.12(y-8)-(0.04y-0.014)=0

We multiply parentheses

0.20y+0.12y-(0.04y-0.014)-0.96=0

We get rid of parentheses

0.20y+0.12y-0.04y+0.014-0.96=0

We add all the numbers together, and all the variables

0.28y-0.946=0

We move all terms containing y to the left, all other terms to the right

0.28y=0.946

y=0.946/0.28

y=3+0.106/0.28

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