0.12-0.02(x+1)=-0.02(3-x)

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Solution for 0.12-0.02(x+1)=-0.02(3-x) equation: 



0.12-0.02(x+1)=-0.02(3-x)

We move all terms to the left:

0.12-0.02(x+1)-(-0.02(3-x))=0

We add all the numbers together, and all the variables

-0.02(x+1)-(-0.02(-1x+3))+0.12=0

We multiply parentheses

-0.02x-(-0.02(-1x+3))-0.02+0.12=0



We calculate terms in parentheses: -(-0.02(-1x+3)), so:

-0.02(-1x+3)

We multiply parentheses

0.02x-0.06

Back to the equation:

-(0.02x-0.06)



We add all the numbers together, and all the variables

-0.02x-(0.02x-0.06)+0.1=0

We get rid of parentheses

-0.02x-0.02x+0.06+0.1=0

We add all the numbers together, and all the variables

-0.04x+0.16=0

We move all terms containing x to the left, all other terms to the right

-0.04x=-0.16

x=-0.16/-0.04

x=+4

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