0.125(2/3x)+0.08(1/4)x+0.06(1/12)x=1625

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Solution for 0.125(2/3x)+0.08(1/4)x+0.06(1/12)x=1625 equation: 



0.125(2/3x)+0.08(1/4)x+0.06(1/12)x=1625

We move all terms to the left:

0.125(2/3x)+0.08(1/4)x+0.06(1/12)x-(1625)=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 12)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

0.125(+2/3x)+0.08(+1/4)x+0.06(+1/12)x-1625=0

We multiply parentheses

0x^2+0x^2+0.25x-1625=0

We add all the numbers together, and all the variables

2x^2+0.25x-1625=0

a = 2; b = 0.25; c = -1625;
Δ = b2-4ac
Δ = 0.252-4·2·(-1625)
Δ = 13000.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.25)-\sqrt{13000.0625}}{2*2}=\frac{-0.25-\sqrt{13000.0625}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.25)+\sqrt{13000.0625}}{2*2}=\frac{-0.25+\sqrt{13000.0625}}{4}
$

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