0.12=0.2(80-x)=12

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Solution for 0.12=0.2(80-x)=12 equation: 



0.12=0.2(80-x)=12

We move all terms to the left:

0.12-(0.2(80-x))=0

We add all the numbers together, and all the variables

-(0.2(-1x+80))+0.12=0



We calculate terms in parentheses: -(0.2(-1x+80)), so:

0.2(-1x+80)

We multiply parentheses

-0.2x+16

Back to the equation:

-(-0.2x+16)



We get rid of parentheses

0.2x-16+0.12=0

We add all the numbers together, and all the variables

0.2x-15.88=0

We move all terms containing x to the left, all other terms to the right

0.2x=15.88

x=15.88/0.2

x=79+0.08/0.2

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