0.12=x(.015)+(1-x)(0.1)

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Solution for 0.12=x(.015)+(1-x)(0.1) equation: 



0.12=x(.015)+(1-x)(0.1)

We move all terms to the left:

0.12-(x(.015)+(1-x)(0.1))=0

We add all the numbers together, and all the variables

-(x(0.015)+(-1x+1)(0.1))+0.12=0

We multiply parentheses ..

-(x(0.015)+(-0.1x+0.1))+0.12=0



We calculate terms in parentheses: -(x(0.015)+(-0.1x+0.1)), so:

x(0.015)+(-0.1x+0.1)

We multiply parentheses

0.015x+(-0.1x+0.1)

We get rid of parentheses

0.015x-0.1x+0.1

We add all the numbers together, and all the variables

-0.085x+0.1

Back to the equation:

-(-0.085x+0.1)



We get rid of parentheses

0.085x-0.1+0.12=0

We add all the numbers together, and all the variables

0.085x+0.02=0

We move all terms containing x to the left, all other terms to the right

0.085x=-0.02

x=-0.02/0.085

x=-0.02/0.085

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