0.12=x(0.15)+(1-x)(0.1)

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Solution for 0.12=x(0.15)+(1-x)(0.1) equation: 



0.12=x(0.15)+(1-x)(0.1)

We move all terms to the left:

0.12-(x(0.15)+(1-x)(0.1))=0

We add all the numbers together, and all the variables

-(x(0.15)+(-1x+1)(0.1))+0.12=0

We multiply parentheses ..

-(x(0.15)+(-0.1x+0.1))+0.12=0



We calculate terms in parentheses: -(x(0.15)+(-0.1x+0.1)), so:

x(0.15)+(-0.1x+0.1)

We multiply parentheses

0.15x+(-0.1x+0.1)

We get rid of parentheses

0.15x-0.1x+0.1

We add all the numbers together, and all the variables

0.05x+0.1

Back to the equation:

-(0.05x+0.1)



We get rid of parentheses

-0.05x-0.1+0.12=0

We add all the numbers together, and all the variables

-0.05x+0.02=0

We move all terms containing x to the left, all other terms to the right

-0.05x=-0.02

x=-0.02/-0.05

x=0.02/0.05

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