0.12x+(16-0.2x)=12

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Solution for 0.12x+(16-0.2x)=12 equation:



0.12x+(16-0.2x)=12
We move all terms to the left:
0.12x+(16-0.2x)-(12)=0
We add all the numbers together, and all the variables
0.12x+(-0.2x+16)-12=0
We get rid of parentheses
0.12x-0.2x+16-12=0
We add all the numbers together, and all the variables
-0.08x+4=0
We move all terms containing x to the left, all other terms to the right
-0.08x=-4
x=-4/-0.08
x=+50

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