0.12x+(2800-0.2x)=2000

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Solution for 0.12x+(2800-0.2x)=2000 equation: 



0.12x+(2800-0.2x)=2000

We move all terms to the left:

0.12x+(2800-0.2x)-(2000)=0

We add all the numbers together, and all the variables

0.12x+(-0.2x+2800)-2000=0

We get rid of parentheses

0.12x-0.2x+2800-2000=0

We add all the numbers together, and all the variables

-0.08x+800=0

We move all terms containing x to the left, all other terms to the right

-0.08x=-800

x=-800/-0.08

x=+10000

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