0.12x+0.07(x-5)=0.01(5x-3)

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Solution for 0.12x+0.07(x-5)=0.01(5x-3) equation: 



0.12x+0.07(x-5)=0.01(5x-3)

We move all terms to the left:

0.12x+0.07(x-5)-(0.01(5x-3))=0

We multiply parentheses

0.12x+0.07x-(0.01(5x-3))-0.35=0



We calculate terms in parentheses: -(0.01(5x-3)), so:

0.01(5x-3)

We multiply parentheses

0.05x-0.03

Back to the equation:

-(0.05x-0.03)



We add all the numbers together, and all the variables

0.19x-(0.05x-0.03)-0.35=0

We get rid of parentheses

0.19x-0.05x+0.03-0.35=0

We add all the numbers together, and all the variables

0.14x-0.32=0

We move all terms containing x to the left, all other terms to the right

0.14x=0.32

x=0.32/0.14

x=2+0.04/0.14

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