0.12x+0.2(10-x)=(0.14)(10)

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Solution for 0.12x+0.2(10-x)=(0.14)(10) equation: 



0.12x+0.2(10-x)=(0.14)(10)

We move all terms to the left:

0.12x+0.2(10-x)-((0.14)(10))=0

We add all the numbers together, and all the variables

0.12x+0.2(-1x+10)-((0.14)10)=0

We add all the numbers together, and all the variables

0.12x+0.2(-1x+10)-1.4=0

We multiply parentheses

0.12x-0.2x+2-1.4=0

We add all the numbers together, and all the variables

-0.08x+0.6=0

We move all terms containing x to the left, all other terms to the right

-0.08x=-0.6

x=-0.6/-0.08

x=7+0.04/0.08

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