0.12x+0.2(10-x)=(0.14)(10)

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Solution for 0.12x+0.2(10-x)=(0.14)(10) equation:



0.12x+0.2(10-x)=(0.14)(10)
We move all terms to the left:
0.12x+0.2(10-x)-((0.14)(10))=0
We add all the numbers together, and all the variables
0.12x+0.2(-1x+10)-((0.14)10)=0
We add all the numbers together, and all the variables
0.12x+0.2(-1x+10)-1.4=0
We multiply parentheses
0.12x-0.2x+2-1.4=0
We add all the numbers together, and all the variables
-0.08x+0.6=0
We move all terms containing x to the left, all other terms to the right
-0.08x=-0.6
x=-0.6/-0.08
x=7+0.04/0.08

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