0.12x+0.2(80-x)=12

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Solution for 0.12x+0.2(80-x)=12 equation: 



0.12x+0.2(80-x)=12

We move all terms to the left:

0.12x+0.2(80-x)-(12)=0

We add all the numbers together, and all the variables

0.12x+0.2(-1x+80)-12=0

We multiply parentheses

0.12x-0.2x+16-12=0

We add all the numbers together, and all the variables

-0.08x+4=0

We move all terms containing x to the left, all other terms to the right

-0.08x=-4

x=-4/-0.08

x=+50

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