0.12x+0.3(x-1)=0.01(3x-4)

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Solution for 0.12x+0.3(x-1)=0.01(3x-4) equation: 



0.12x+0.3(x-1)=0.01(3x-4)

We move all terms to the left:

0.12x+0.3(x-1)-(0.01(3x-4))=0

We multiply parentheses

0.12x+0.3x-(0.01(3x-4))-0.3=0



We calculate terms in parentheses: -(0.01(3x-4)), so:

0.01(3x-4)

We multiply parentheses

0.03x-0.04

Back to the equation:

-(0.03x-0.04)



We add all the numbers together, and all the variables

0.42x-(0.03x-0.04)-0.3=0

We get rid of parentheses

0.42x-0.03x+0.04-0.3=0

We add all the numbers together, and all the variables

0.39x-0.26=0

We move all terms containing x to the left, all other terms to the right

0.39x=0.26

x=0.26/0.39

x=0.26/0.39

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