0.12x+0.3(x-3)=0.01(3x-2)

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Solution for 0.12x+0.3(x-3)=0.01(3x-2) equation: 



0.12x+0.3(x-3)=0.01(3x-2)

We move all terms to the left:

0.12x+0.3(x-3)-(0.01(3x-2))=0

We multiply parentheses

0.12x+0.3x-(0.01(3x-2))-0.9=0



We calculate terms in parentheses: -(0.01(3x-2)), so:

0.01(3x-2)

We multiply parentheses

0.03x-0.02

Back to the equation:

-(0.03x-0.02)



We add all the numbers together, and all the variables

0.42x-(0.03x-0.02)-0.9=0

We get rid of parentheses

0.42x-0.03x+0.02-0.9=0

We add all the numbers together, and all the variables

0.39x-0.88=0

We move all terms containing x to the left, all other terms to the right

0.39x=0.88

x=0.88/0.39

x=2+0.1/0.39

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