0.12x+0.7(x-5)=0.01(5x-1)

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Solution for 0.12x+0.7(x-5)=0.01(5x-1) equation: 



0.12x+0.7(x-5)=0.01(5x-1)

We move all terms to the left:

0.12x+0.7(x-5)-(0.01(5x-1))=0

We multiply parentheses

0.12x+0.7x-(0.01(5x-1))-3.5=0



We calculate terms in parentheses: -(0.01(5x-1)), so:

0.01(5x-1)

We multiply parentheses

0.05x-0.01

Back to the equation:

-(0.05x-0.01)



We add all the numbers together, and all the variables

0.82x-(0.05x-0.01)-3.5=0

We get rid of parentheses

0.82x-0.05x+0.01-3.5=0

We add all the numbers together, and all the variables

0.77x-3.49=0

We move all terms containing x to the left, all other terms to the right

0.77x=3.49

x=3.49/0.77

x=4+0.41/0.77

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