0.12x+0.7(x-5)=0.01(5x-1)

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Solution for 0.12x+0.7(x-5)=0.01(5x-1) equation:



0.12x+0.7(x-5)=0.01(5x-1)
We move all terms to the left:
0.12x+0.7(x-5)-(0.01(5x-1))=0
We multiply parentheses
0.12x+0.7x-(0.01(5x-1))-3.5=0
We calculate terms in parentheses: -(0.01(5x-1)), so:
0.01(5x-1)
We multiply parentheses
0.05x-0.01
Back to the equation:
-(0.05x-0.01)
We add all the numbers together, and all the variables
0.82x-(0.05x-0.01)-3.5=0
We get rid of parentheses
0.82x-0.05x+0.01-3.5=0
We add all the numbers together, and all the variables
0.77x-3.49=0
We move all terms containing x to the left, all other terms to the right
0.77x=3.49
x=3.49/0.77
x=4+0.41/0.77

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