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0.13=x(x-1)
We move all terms to the left:
0.13-(x(x-1))=0
We calculate terms in parentheses: -(x(x-1)), so:We get rid of parentheses
x(x-1)
We multiply parentheses
x^2-1x
Back to the equation:
-(x^2-1x)
-x^2+1x+0.13=0
We add all the numbers together, and all the variables
-1x^2+x+0.13=0
a = -1; b = 1; c = +0.13;
Δ = b2-4ac
Δ = 12-4·(-1)·0.13
Δ = 1.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.52}}{2*-1}=\frac{-1-\sqrt{1.52}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.52}}{2*-1}=\frac{-1+\sqrt{1.52}}{-2} $
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