0.13x+0.7(x-2)=0.01(4x-1)

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Solution for 0.13x+0.7(x-2)=0.01(4x-1) equation: 



0.13x+0.7(x-2)=0.01(4x-1)

We move all terms to the left:

0.13x+0.7(x-2)-(0.01(4x-1))=0

We multiply parentheses

0.13x+0.7x-(0.01(4x-1))-1.4=0



We calculate terms in parentheses: -(0.01(4x-1)), so:

0.01(4x-1)

We multiply parentheses

0.04x-0.01

Back to the equation:

-(0.04x-0.01)



We add all the numbers together, and all the variables

0.83x-(0.04x-0.01)-1.4=0

We get rid of parentheses

0.83x-0.04x+0.01-1.4=0

We add all the numbers together, and all the variables

0.79x-1.39=0

We move all terms containing x to the left, all other terms to the right

0.79x=1.39

x=1.39/0.79

x=1+0.6/0.79

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