0.14(y-7)+0.08y=0.12y-0.03(20)

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Solution for 0.14(y-7)+0.08y=0.12y-0.03(20) equation: 



0.14(y-7)+0.08y=0.12y-0.03(20)

We move all terms to the left:

0.14(y-7)+0.08y-(0.12y-0.03(20))=0

We add all the numbers together, and all the variables

0.14(y-7)+0.08y-(0.12y-0.032)=0

We add all the numbers together, and all the variables

0.08y+0.14(y-7)-(0.12y-0.032)=0

We multiply parentheses

0.08y+0.14y-(0.12y-0.032)-0.98=0

We get rid of parentheses

0.08y+0.14y-0.12y+0.032-0.98=0

We add all the numbers together, and all the variables

0.1y-0.948=0

We move all terms containing y to the left, all other terms to the right

0.1y=0.948

y=0.948/0.1

y=9+0.048/0.1

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