0.14-0.01(y+2)=-0.03(4-y)

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Solution for 0.14-0.01(y+2)=-0.03(4-y) equation:



0.14-0.01(y+2)=-0.03(4-y)
We move all terms to the left:
0.14-0.01(y+2)-(-0.03(4-y))=0
We add all the numbers together, and all the variables
-0.01(y+2)-(-0.03(-1y+4))+0.14=0
We multiply parentheses
-0.01y-(-0.03(-1y+4))-0.02+0.14=0
We calculate terms in parentheses: -(-0.03(-1y+4)), so:
-0.03(-1y+4)
We multiply parentheses
0.03y-0.12
Back to the equation:
-(0.03y-0.12)
We add all the numbers together, and all the variables
-0.01y-(0.03y-0.12)+0.12=0
We get rid of parentheses
-0.01y-0.03y+0.12+0.12=0
We add all the numbers together, and all the variables
-0.04y+0.24=0
We move all terms containing y to the left, all other terms to the right
-0.04y=-0.24
y=-0.24/-0.04
y=+6

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