0.14-0.02(x+2)=0.04(2-x)

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Solution for 0.14-0.02(x+2)=0.04(2-x) equation:



0.14-0.02(x+2)=0.04(2-x)
We move all terms to the left:
0.14-0.02(x+2)-(0.04(2-x))=0
We add all the numbers together, and all the variables
-0.02(x+2)-(0.04(-1x+2))+0.14=0
We multiply parentheses
-0.02x-(0.04(-1x+2))-0.04+0.14=0
We calculate terms in parentheses: -(0.04(-1x+2)), so:
0.04(-1x+2)
We multiply parentheses
-0.04x+0.08
Back to the equation:
-(-0.04x+0.08)
We add all the numbers together, and all the variables
-0.02x-(-0.04x+0.08)+0.1=0
We get rid of parentheses
-0.02x+0.04x-0.08+0.1=0
We add all the numbers together, and all the variables
0.02x+0.02=0
We move all terms containing x to the left, all other terms to the right
0.02x=-0.02
x=-0.02/0.02
x=-1

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