0.14=y(y-0.045)(0.72)

Solution for 0.14=y(y-0.045)(0.72) equation:

0.14=y(y-0.045)(0.72)

We move all terms to the left:

0.14-(y(y-0.045)(0.72))=0

We multiply parentheses ..

-(y(+0.72y-0.0324))+0.14=0


We calculate terms in parentheses: -(y(+0.72y-0.0324)), so:

y(+0.72y-0.0324)

We add all the numbers together, and all the variables

y(0.72y-0.0324)

We multiply parentheses

0y^2-0.0324y

We add all the numbers together, and all the variables

y^2-0.0324y

Back to the equation:

-(y^2-0.0324y)


We get rid of parentheses

-y^2+0.0324y+0.14=0

We add all the numbers together, and all the variables

-1y^2+0.0324y+0.14=0

a = -1; b = 0.0324; c = +0.14;
Δ = b2-4ac
Δ = 0.03242-4·(-1)·0.14
Δ = 0.56104976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.0324)-\sqrt{0.56104976}}{2*-1}=\frac{-0.0324-\sqrt{0.56104976}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.0324)+\sqrt{0.56104976}}{2*-1}=\frac{-0.0324+\sqrt{0.56104976}}{-2}
$