0.14x+0.8(x-2)=0.01(4x-2)

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Solution for 0.14x+0.8(x-2)=0.01(4x-2) equation: 



0.14x+0.8(x-2)=0.01(4x-2)

We move all terms to the left:

0.14x+0.8(x-2)-(0.01(4x-2))=0

We multiply parentheses

0.14x+0.8x-(0.01(4x-2))-1.6=0



We calculate terms in parentheses: -(0.01(4x-2)), so:

0.01(4x-2)

We multiply parentheses

0.04x-0.02

Back to the equation:

-(0.04x-0.02)



We add all the numbers together, and all the variables

0.94x-(0.04x-0.02)-1.6=0

We get rid of parentheses

0.94x-0.04x+0.02-1.6=0

We add all the numbers together, and all the variables

0.9x-1.58=0

We move all terms containing x to the left, all other terms to the right

0.9x=1.58

x=1.58/0.9

x=1+0.68/0.9

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