0.15x+0.3(x-4)=0.01(4x-2)

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Solution for 0.15x+0.3(x-4)=0.01(4x-2) equation: 



0.15x+0.3(x-4)=0.01(4x-2)

We move all terms to the left:

0.15x+0.3(x-4)-(0.01(4x-2))=0

We multiply parentheses

0.15x+0.3x-(0.01(4x-2))-1.2=0



We calculate terms in parentheses: -(0.01(4x-2)), so:

0.01(4x-2)

We multiply parentheses

0.04x-0.02

Back to the equation:

-(0.04x-0.02)



We add all the numbers together, and all the variables

0.45x-(0.04x-0.02)-1.2=0

We get rid of parentheses

0.45x-0.04x+0.02-1.2=0

We add all the numbers together, and all the variables

0.41x-1.18=0

We move all terms containing x to the left, all other terms to the right

0.41x=1.18

x=1.18/0.41

x=2+0.36/0.41

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