0.16(y-2)+0.08y=0.12y-0.01(20)

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Solution for 0.16(y-2)+0.08y=0.12y-0.01(20) equation:



0.16(y-2)+0.08y=0.12y-0.01(20)
We move all terms to the left:
0.16(y-2)+0.08y-(0.12y-0.01(20))=0
We add all the numbers together, and all the variables
0.16(y-2)+0.08y-(0.12y-0.012)=0
We add all the numbers together, and all the variables
0.08y+0.16(y-2)-(0.12y-0.012)=0
We multiply parentheses
0.08y+0.16y-(0.12y-0.012)-0.32=0
We get rid of parentheses
0.08y+0.16y-0.12y+0.012-0.32=0
We add all the numbers together, and all the variables
0.12y-0.308=0
We move all terms containing y to the left, all other terms to the right
0.12y=0.308
y=0.308/0.12
y=2+0.068/0.12

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