0.16(y-7)+0.12y=0.18y-0.03(20)

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Solution for 0.16(y-7)+0.12y=0.18y-0.03(20) equation: 



0.16(y-7)+0.12y=0.18y-0.03(20)

We move all terms to the left:

0.16(y-7)+0.12y-(0.18y-0.03(20))=0

We add all the numbers together, and all the variables

0.16(y-7)+0.12y-(0.18y-0.032)=0

We add all the numbers together, and all the variables

0.12y+0.16(y-7)-(0.18y-0.032)=0

We multiply parentheses

0.12y+0.16y-(0.18y-0.032)-1.12=0

We get rid of parentheses

0.12y+0.16y-0.18y+0.032-1.12=0

We add all the numbers together, and all the variables

0.1y-1.088=0

We move all terms containing y to the left, all other terms to the right

0.1y=1.088

y=1.088/0.1

y=10+0.088/0.1

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