0.16y+0.02y(y+3000)=960

Solution for 0.16y+0.02y(y+3000)=960 equation:

0.16y+0.02y(y+3000)=960

We move all terms to the left:

0.16y+0.02y(y+3000)-(960)=0

We multiply parentheses

0y^2+0.16y+0y-960=0

We add all the numbers together, and all the variables

y^2+1.16y-960=0

a = 1; b = 1.16; c = -960;
Δ = b2-4ac
Δ = 1.162-4·1·(-960)
Δ = 3841.3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.16)-\sqrt{3841.3456}}{2*1}=\frac{-1.16-\sqrt{3841.3456}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.16)+\sqrt{3841.3456}}{2*1}=\frac{-1.16+\sqrt{3841.3456}}{2}
$