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0.18t^2-2t-5.2=0
a = 0.18; b = -2; c = -5.2;
Δ = b2-4ac
Δ = -22-4·0.18·(-5.2)
Δ = 7.744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{7.744}}{2*0.18}=\frac{2-\sqrt{7.744}}{0.36} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{7.744}}{2*0.18}=\frac{2+\sqrt{7.744}}{0.36} $
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