0.1d+0.01(d+2)=2

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Solution for 0.1d+0.01(d+2)=2 equation: 



0.1d+0.01(d+2)=2

We move all terms to the left:

0.1d+0.01(d+2)-(2)=0

We multiply parentheses

0.1d+0.01d+0.02-2=0

We add all the numbers together, and all the variables

0.11d-1.98=0

We move all terms containing d to the left, all other terms to the right

0.11d=1.98

d=1.98/0.11

d=18

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