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0.1x^2-0.8x+1.6=0
a = 0.1; b = -0.8; c = +1.6;
Δ = b2-4ac
Δ = -0.82-4·0.1·1.6
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0.8}{0.2}=4$
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