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0.1x^2-1.992x+0.00016=0
a = 0.1; b = -1.992; c = +0.00016;
Δ = b2-4ac
Δ = -1.9922-4·0.1·0.00016
Δ = 3.968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.992)-\sqrt{3.968}}{2*0.1}=\frac{1.992-\sqrt{3.968}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.992)+\sqrt{3.968}}{2*0.1}=\frac{1.992+\sqrt{3.968}}{0.2} $
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