0.1y+0.9(12-y)=6

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Solution for 0.1y+0.9(12-y)=6 equation: 



0.1y+0.9(12-y)=6

We move all terms to the left:

0.1y+0.9(12-y)-(6)=0

We add all the numbers together, and all the variables

0.1y+0.9(-1y+12)-6=0

We multiply parentheses

0.1y-0.9y+10.8-6=0

We add all the numbers together, and all the variables

-0.8y+4.8=0

We move all terms containing y to the left, all other terms to the right

-0.8y=-4.8

y=-4.8/-0.8

y=5+0.8/0.8

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