0.2(10t-4)t=1.2

Solution for 0.2(10t-4)t=1.2 equation:

0.2(10t-4)t=1.2

We move all terms to the left:

0.2(10t-4)t-(1.2)=0

We add all the numbers together, and all the variables

0.2(10t-4)t-1.2=0

We multiply parentheses

0t^2+0t-1.2=0

We add all the numbers together, and all the variables

t^2+t-1.2=0

a = 1; b = 1; c = -1.2;
Δ = b2-4ac
Δ = 12-4·1·(-1.2)
Δ = 5.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{5.8}}{2*1}=\frac{-1-\sqrt{5.8}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{5.8}}{2*1}=\frac{-1+\sqrt{5.8}}{2}
$