0.2(10x+40)+3x=4x+22

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Solution for 0.2(10x+40)+3x=4x+22 equation: 



0.2(10x+40)+3x=4x+22

We move all terms to the left:

0.2(10x+40)+3x-(4x+22)=0

We add all the numbers together, and all the variables

3x+0.2(10x+40)-(4x+22)=0

We multiply parentheses

3x+2x-(4x+22)+8=0

We get rid of parentheses

3x+2x-4x-22+8=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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