0.2(d-10)=0.4d+7-3+0.2d

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Solution for 0.2(d-10)=0.4d+7-3+0.2d equation: 



0.2(d-10)=0.4d+7-3+0.2d

We move all terms to the left:

0.2(d-10)-(0.4d+7-3+0.2d)=0

We add all the numbers together, and all the variables

0.2(d-10)-(0.6d+4)=0

We multiply parentheses

0.2d-(0.6d+4)-2=0

We get rid of parentheses

0.2d-0.6d-4-2=0

We add all the numbers together, and all the variables

-0.4d-6=0

We move all terms containing d to the left, all other terms to the right

-0.4d=6

d=6/-0.4

d=-15

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