0.2(i-6)=0.3i+5-3+0.1i

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Solution for 0.2(i-6)=0.3i+5-3+0.1i equation: 



0.2(i-6)=0.3i+5-3+0.1i

We move all terms to the left:

0.2(i-6)-(0.3i+5-3+0.1i)=0

We add all the numbers together, and all the variables

0.2(i-6)-(0.4i+2)=0

We multiply parentheses

0.2i-(0.4i+2)-1.2=0

We get rid of parentheses

0.2i-0.4i-2-1.2=0

We add all the numbers together, and all the variables

-0.2i-3.2=0

We move all terms containing i to the left, all other terms to the right

-0.2i=3.2

i=3.2/-0.2

i=-16

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