0.2(x+2)=0.5(x+2)-0.2x-0.4

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Solution for 0.2(x+2)=0.5(x+2)-0.2x-0.4 equation: 



0.2(x+2)=0.5(x+2)-0.2x-0.4

We move all terms to the left:

0.2(x+2)-(0.5(x+2)-0.2x-0.4)=0

We multiply parentheses

0.2x-(0.5(x+2)-0.2x-0.4)+0.4=0



We calculate terms in parentheses: -(0.5(x+2)-0.2x-0.4), so:

0.5(x+2)-0.2x-0.4

We add all the numbers together, and all the variables

-0.2x+0.5(x+2)-0.4

We multiply parentheses

-0.2x+0.5x+1-0.4

We add all the numbers together, and all the variables

0.3x+0.6

Back to the equation:

-(0.3x+0.6)



We get rid of parentheses

0.2x-0.3x-0.6+0.4=0

We add all the numbers together, and all the variables

-0.1x-0.2=0

We move all terms containing x to the left, all other terms to the right

-0.1x=0.2

x=0.2/-0.1

x=-2

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