0.2(y+50)-6=0.4(3y+20)

Solution for 0.2(y+50)-6=0.4(3y+20) equation:

0.2(y+50)-6=0.4(3y+20)

We move all terms to the left:

0.2(y+50)-6-(0.4(3y+20))=0

We multiply parentheses

0.2y-(0.4(3y+20))+10-6=0


We calculate terms in parentheses: -(0.4(3y+20)), so:

0.4(3y+20)

We multiply parentheses

1.2y+8

Back to the equation:

-(1.2y+8)


We add all the numbers together, and all the variables

0.2y-(1.2y+8)+4=0

We get rid of parentheses

0.2y-1.2y-8+4=0

We add all the numbers together, and all the variables

-1y-4=0

We move all terms containing y to the left, all other terms to the right

-y=4

y=4/-1

y=-4