0.2(y-4)+0.08y=0.12y-0.2

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Solution for 0.2(y-4)+0.08y=0.12y-0.2 equation: 



0.2(y-4)+0.08y=0.12y-0.2

We move all terms to the left:

0.2(y-4)+0.08y-(0.12y-0.2)=0

We add all the numbers together, and all the variables

0.08y+0.2(y-4)-(0.12y-0.2)=0

We multiply parentheses

0.08y+0.2y-(0.12y-0.2)-0.8=0

We get rid of parentheses

0.08y+0.2y-0.12y+0.2-0.8=0

We add all the numbers together, and all the variables

0.16y-0.6=0

We move all terms containing y to the left, all other terms to the right

0.16y=0.6

y=0.6/0.16

y=3+0.12/0.16

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