0.21-0.03(x+2)=-0.01(1-x)

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Solution for 0.21-0.03(x+2)=-0.01(1-x) equation: 



0.21-0.03(x+2)=-0.01(1-x)

We move all terms to the left:

0.21-0.03(x+2)-(-0.01(1-x))=0

We add all the numbers together, and all the variables

-0.03(x+2)-(-0.01(-1x+1))+0.21=0

We multiply parentheses

-0.03x-(-0.01(-1x+1))-0.06+0.21=0



We calculate terms in parentheses: -(-0.01(-1x+1)), so:

-0.01(-1x+1)

We multiply parentheses

0.01x-0.01

Back to the equation:

-(0.01x-0.01)



We add all the numbers together, and all the variables

-0.03x-(0.01x-0.01)+0.15=0

We get rid of parentheses

-0.03x-0.01x+0.01+0.15=0

We add all the numbers together, and all the variables

-0.04x+0.16=0

We move all terms containing x to the left, all other terms to the right

-0.04x=-0.16

x=-0.16/-0.04

x=+4

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