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0.211=x(1-x)
We move all terms to the left:
0.211-(x(1-x))=0
We add all the numbers together, and all the variables
-(x(-1x+1))+0.211=0
We calculate terms in parentheses: -(x(-1x+1)), so:We get rid of parentheses
x(-1x+1)
We multiply parentheses
-1x^2+x
Back to the equation:
-(-1x^2+x)
1x^2-x+0.211=0
We add all the numbers together, and all the variables
x^2-1x+0.211=0
a = 1; b = -1; c = +0.211;
Δ = b2-4ac
Δ = -12-4·1·0.211
Δ = 0.156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.156}}{2*1}=\frac{1-\sqrt{0.156}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.156}}{2*1}=\frac{1+\sqrt{0.156}}{2} $
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