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0.22x(x+9)=0.2x+3.9
We move all terms to the left:
0.22x(x+9)-(0.2x+3.9)=0
We multiply parentheses
0x^2+0x-(0.2x+3.9)=0
We get rid of parentheses
0x^2+0x-0.2x-3.9=0
We add all the numbers together, and all the variables
x^2+0.8x-3.9=0
a = 1; b = 0.8; c = -3.9;
Δ = b2-4ac
Δ = 0.82-4·1·(-3.9)
Δ = 16.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.8)-\sqrt{16.24}}{2*1}=\frac{-0.8-\sqrt{16.24}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.8)+\sqrt{16.24}}{2*1}=\frac{-0.8+\sqrt{16.24}}{2} $
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