0.24-0.02(x+1)=-0.03(1-x)

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Solution for 0.24-0.02(x+1)=-0.03(1-x) equation: 



0.24-0.02(x+1)=-0.03(1-x)

We move all terms to the left:

0.24-0.02(x+1)-(-0.03(1-x))=0

We add all the numbers together, and all the variables

-0.02(x+1)-(-0.03(-1x+1))+0.24=0

We multiply parentheses

-0.02x-(-0.03(-1x+1))-0.02+0.24=0



We calculate terms in parentheses: -(-0.03(-1x+1)), so:

-0.03(-1x+1)

We multiply parentheses

0.03x-0.03

Back to the equation:

-(0.03x-0.03)



We add all the numbers together, and all the variables

-0.02x-(0.03x-0.03)+0.22=0

We get rid of parentheses

-0.02x-0.03x+0.03+0.22=0

We add all the numbers together, and all the variables

-0.05x+0.25=0

We move all terms containing x to the left, all other terms to the right

-0.05x=-0.25

x=-0.25/-0.05

x=+5

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